PITTSBURGH -- For the second time this year, Steelers quarterback Ben Roethlisberger has been named the AFC Offensive Player of the Week.
Roethlisberger completed 36 of 50 pass attempts for a season-high 365 yards and two touchdowns on Sunday, when the Steelers beat the New England Patriots 25-17.
Roethlisberger also won the AFC weekly award after the Steelers' Oct. 9 victory over the Tennessee Titans
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