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View Full Version : Bobby April extricates himself.



steelblood
01-05-2010, 12:57 PM
Bills claim coaches not all fired. Bobby April has exercised a clause in his contract to make him a "coaching free agent."
http://www.buffalorumblings.com/2010/1/ ... ?ref=yahoo (http://www.buffalorumblings.com/2010/1/5/1234835/espn-say-goodbye-to-bobby-april?ref=yahoo)

Hire him now! If we don't get him in for an interview tomorrow, Tomlin and Colbert and not doing their jobs. Geez, I hope Shanahan hasn't already talked to him. Snyder will pay him more than we can afford.

Oviedo
01-05-2010, 01:03 PM
Bills claim coaches not all fired. Bobby April has exercised a clause in his contract to make him a "coaching free agent."
http://www.buffalorumblings.com/2010/1/ ... ?ref=yahoo (http://www.buffalorumblings.com/2010/1/5/1234835/espn-say-goodbye-to-bobby-april?ref=yahoo)

Hire him now! If we don't get him in for an interview tomorrow, Tomlin and Colbert and not doing their jobs. Geez, I hope Shanahan hasn't already talked to him. Snyder will pay him more than we can afford.

:Agree Get him now and then we will know whether it is coach or players.

phillyesq
01-05-2010, 01:27 PM
:Agree

The ST have been absolutely terrible for at least 1.5 of the 3 seasons Ligashesky was here. They improved with the addition of Madison and a few other guys this year, and they were generally good last year, although he needed James Harrison, the D-MVP, among others, for his unit to be effective.

steelblood
01-06-2010, 09:02 AM
:Agree

The ST have been absolutely terrible for at least 1.5 of the 3 seasons Ligashesky was here. They improved with the addition of Madison and a few other guys this year, and they were generally good last year, although he needed James Harrison, the D-MVP, among others, for his unit to be effective.


Tomlin wants to meet with all of the players and PS players before meeting with the coaches and making a decision. This is prudent and stupid. April and other good options will likely be hired by the time he gets around to firing Ligashevsky.